Optimal. Leaf size=499 \[ \frac {3 i b^2 c \text {Li}_2\left (1-\frac {2}{1-i c x}\right ) \left (a+b \tan ^{-1}(c x)\right )}{c^2 d^2+e^2}+\frac {3 i b^2 c \text {Li}_2\left (1-\frac {2}{i c x+1}\right ) \left (a+b \tan ^{-1}(c x)\right )}{c^2 d^2+e^2}-\frac {3 i b^2 c \left (a+b \tan ^{-1}(c x)\right ) \text {Li}_2\left (1-\frac {2 c (d+e x)}{(c d+i e) (1-i c x)}\right )}{c^2 d^2+e^2}+\frac {i c \left (a+b \tan ^{-1}(c x)\right )^3}{c^2 d^2+e^2}+\frac {c^2 d \left (a+b \tan ^{-1}(c x)\right )^3}{e \left (c^2 d^2+e^2\right )}-\frac {3 b c \log \left (\frac {2}{1-i c x}\right ) \left (a+b \tan ^{-1}(c x)\right )^2}{c^2 d^2+e^2}+\frac {3 b c \log \left (\frac {2}{1+i c x}\right ) \left (a+b \tan ^{-1}(c x)\right )^2}{c^2 d^2+e^2}+\frac {3 b c \left (a+b \tan ^{-1}(c x)\right )^2 \log \left (\frac {2 c (d+e x)}{(1-i c x) (c d+i e)}\right )}{c^2 d^2+e^2}-\frac {\left (a+b \tan ^{-1}(c x)\right )^3}{e (d+e x)}-\frac {3 b^3 c \text {Li}_3\left (1-\frac {2}{1-i c x}\right )}{2 \left (c^2 d^2+e^2\right )}+\frac {3 b^3 c \text {Li}_3\left (1-\frac {2}{i c x+1}\right )}{2 \left (c^2 d^2+e^2\right )}+\frac {3 b^3 c \text {Li}_3\left (1-\frac {2 c (d+e x)}{(c d+i e) (1-i c x)}\right )}{2 \left (c^2 d^2+e^2\right )} \]
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Rubi [A] time = 0.53, antiderivative size = 499, normalized size of antiderivative = 1.00, number of steps used = 10, number of rules used = 8, integrand size = 18, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.444, Rules used = {4864, 4858, 4984, 4884, 4920, 4854, 4994, 6610} \[ \frac {3 i b^2 c \text {PolyLog}\left (2,1-\frac {2}{1-i c x}\right ) \left (a+b \tan ^{-1}(c x)\right )}{c^2 d^2+e^2}+\frac {3 i b^2 c \text {PolyLog}\left (2,1-\frac {2}{1+i c x}\right ) \left (a+b \tan ^{-1}(c x)\right )}{c^2 d^2+e^2}-\frac {3 i b^2 c \left (a+b \tan ^{-1}(c x)\right ) \text {PolyLog}\left (2,1-\frac {2 c (d+e x)}{(1-i c x) (c d+i e)}\right )}{c^2 d^2+e^2}-\frac {3 b^3 c \text {PolyLog}\left (3,1-\frac {2}{1-i c x}\right )}{2 \left (c^2 d^2+e^2\right )}+\frac {3 b^3 c \text {PolyLog}\left (3,1-\frac {2}{1+i c x}\right )}{2 \left (c^2 d^2+e^2\right )}+\frac {3 b^3 c \text {PolyLog}\left (3,1-\frac {2 c (d+e x)}{(1-i c x) (c d+i e)}\right )}{2 \left (c^2 d^2+e^2\right )}+\frac {i c \left (a+b \tan ^{-1}(c x)\right )^3}{c^2 d^2+e^2}+\frac {c^2 d \left (a+b \tan ^{-1}(c x)\right )^3}{e \left (c^2 d^2+e^2\right )}-\frac {3 b c \log \left (\frac {2}{1-i c x}\right ) \left (a+b \tan ^{-1}(c x)\right )^2}{c^2 d^2+e^2}+\frac {3 b c \log \left (\frac {2}{1+i c x}\right ) \left (a+b \tan ^{-1}(c x)\right )^2}{c^2 d^2+e^2}+\frac {3 b c \left (a+b \tan ^{-1}(c x)\right )^2 \log \left (\frac {2 c (d+e x)}{(1-i c x) (c d+i e)}\right )}{c^2 d^2+e^2}-\frac {\left (a+b \tan ^{-1}(c x)\right )^3}{e (d+e x)} \]
Antiderivative was successfully verified.
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Rule 4854
Rule 4858
Rule 4864
Rule 4884
Rule 4920
Rule 4984
Rule 4994
Rule 6610
Rubi steps
\begin {align*} \int \frac {\left (a+b \tan ^{-1}(c x)\right )^3}{(d+e x)^2} \, dx &=-\frac {\left (a+b \tan ^{-1}(c x)\right )^3}{e (d+e x)}+\frac {(3 b c) \int \left (\frac {e^2 \left (a+b \tan ^{-1}(c x)\right )^2}{\left (c^2 d^2+e^2\right ) (d+e x)}+\frac {c^2 (d-e x) \left (a+b \tan ^{-1}(c x)\right )^2}{\left (c^2 d^2+e^2\right ) \left (1+c^2 x^2\right )}\right ) \, dx}{e}\\ &=-\frac {\left (a+b \tan ^{-1}(c x)\right )^3}{e (d+e x)}+\frac {\left (3 b c^3\right ) \int \frac {(d-e x) \left (a+b \tan ^{-1}(c x)\right )^2}{1+c^2 x^2} \, dx}{e \left (c^2 d^2+e^2\right )}+\frac {(3 b c e) \int \frac {\left (a+b \tan ^{-1}(c x)\right )^2}{d+e x} \, dx}{c^2 d^2+e^2}\\ &=-\frac {\left (a+b \tan ^{-1}(c x)\right )^3}{e (d+e x)}-\frac {3 b c \left (a+b \tan ^{-1}(c x)\right )^2 \log \left (\frac {2}{1-i c x}\right )}{c^2 d^2+e^2}+\frac {3 b c \left (a+b \tan ^{-1}(c x)\right )^2 \log \left (\frac {2 c (d+e x)}{(c d+i e) (1-i c x)}\right )}{c^2 d^2+e^2}+\frac {3 i b^2 c \left (a+b \tan ^{-1}(c x)\right ) \text {Li}_2\left (1-\frac {2}{1-i c x}\right )}{c^2 d^2+e^2}-\frac {3 i b^2 c \left (a+b \tan ^{-1}(c x)\right ) \text {Li}_2\left (1-\frac {2 c (d+e x)}{(c d+i e) (1-i c x)}\right )}{c^2 d^2+e^2}-\frac {3 b^3 c \text {Li}_3\left (1-\frac {2}{1-i c x}\right )}{2 \left (c^2 d^2+e^2\right )}+\frac {3 b^3 c \text {Li}_3\left (1-\frac {2 c (d+e x)}{(c d+i e) (1-i c x)}\right )}{2 \left (c^2 d^2+e^2\right )}+\frac {\left (3 b c^3\right ) \int \left (\frac {d \left (a+b \tan ^{-1}(c x)\right )^2}{1+c^2 x^2}-\frac {e x \left (a+b \tan ^{-1}(c x)\right )^2}{1+c^2 x^2}\right ) \, dx}{e \left (c^2 d^2+e^2\right )}\\ &=-\frac {\left (a+b \tan ^{-1}(c x)\right )^3}{e (d+e x)}-\frac {3 b c \left (a+b \tan ^{-1}(c x)\right )^2 \log \left (\frac {2}{1-i c x}\right )}{c^2 d^2+e^2}+\frac {3 b c \left (a+b \tan ^{-1}(c x)\right )^2 \log \left (\frac {2 c (d+e x)}{(c d+i e) (1-i c x)}\right )}{c^2 d^2+e^2}+\frac {3 i b^2 c \left (a+b \tan ^{-1}(c x)\right ) \text {Li}_2\left (1-\frac {2}{1-i c x}\right )}{c^2 d^2+e^2}-\frac {3 i b^2 c \left (a+b \tan ^{-1}(c x)\right ) \text {Li}_2\left (1-\frac {2 c (d+e x)}{(c d+i e) (1-i c x)}\right )}{c^2 d^2+e^2}-\frac {3 b^3 c \text {Li}_3\left (1-\frac {2}{1-i c x}\right )}{2 \left (c^2 d^2+e^2\right )}+\frac {3 b^3 c \text {Li}_3\left (1-\frac {2 c (d+e x)}{(c d+i e) (1-i c x)}\right )}{2 \left (c^2 d^2+e^2\right )}-\frac {\left (3 b c^3\right ) \int \frac {x \left (a+b \tan ^{-1}(c x)\right )^2}{1+c^2 x^2} \, dx}{c^2 d^2+e^2}+\frac {\left (3 b c^3 d\right ) \int \frac {\left (a+b \tan ^{-1}(c x)\right )^2}{1+c^2 x^2} \, dx}{e \left (c^2 d^2+e^2\right )}\\ &=\frac {i c \left (a+b \tan ^{-1}(c x)\right )^3}{c^2 d^2+e^2}+\frac {c^2 d \left (a+b \tan ^{-1}(c x)\right )^3}{e \left (c^2 d^2+e^2\right )}-\frac {\left (a+b \tan ^{-1}(c x)\right )^3}{e (d+e x)}-\frac {3 b c \left (a+b \tan ^{-1}(c x)\right )^2 \log \left (\frac {2}{1-i c x}\right )}{c^2 d^2+e^2}+\frac {3 b c \left (a+b \tan ^{-1}(c x)\right )^2 \log \left (\frac {2 c (d+e x)}{(c d+i e) (1-i c x)}\right )}{c^2 d^2+e^2}+\frac {3 i b^2 c \left (a+b \tan ^{-1}(c x)\right ) \text {Li}_2\left (1-\frac {2}{1-i c x}\right )}{c^2 d^2+e^2}-\frac {3 i b^2 c \left (a+b \tan ^{-1}(c x)\right ) \text {Li}_2\left (1-\frac {2 c (d+e x)}{(c d+i e) (1-i c x)}\right )}{c^2 d^2+e^2}-\frac {3 b^3 c \text {Li}_3\left (1-\frac {2}{1-i c x}\right )}{2 \left (c^2 d^2+e^2\right )}+\frac {3 b^3 c \text {Li}_3\left (1-\frac {2 c (d+e x)}{(c d+i e) (1-i c x)}\right )}{2 \left (c^2 d^2+e^2\right )}+\frac {\left (3 b c^2\right ) \int \frac {\left (a+b \tan ^{-1}(c x)\right )^2}{i-c x} \, dx}{c^2 d^2+e^2}\\ &=\frac {i c \left (a+b \tan ^{-1}(c x)\right )^3}{c^2 d^2+e^2}+\frac {c^2 d \left (a+b \tan ^{-1}(c x)\right )^3}{e \left (c^2 d^2+e^2\right )}-\frac {\left (a+b \tan ^{-1}(c x)\right )^3}{e (d+e x)}-\frac {3 b c \left (a+b \tan ^{-1}(c x)\right )^2 \log \left (\frac {2}{1-i c x}\right )}{c^2 d^2+e^2}+\frac {3 b c \left (a+b \tan ^{-1}(c x)\right )^2 \log \left (\frac {2}{1+i c x}\right )}{c^2 d^2+e^2}+\frac {3 b c \left (a+b \tan ^{-1}(c x)\right )^2 \log \left (\frac {2 c (d+e x)}{(c d+i e) (1-i c x)}\right )}{c^2 d^2+e^2}+\frac {3 i b^2 c \left (a+b \tan ^{-1}(c x)\right ) \text {Li}_2\left (1-\frac {2}{1-i c x}\right )}{c^2 d^2+e^2}-\frac {3 i b^2 c \left (a+b \tan ^{-1}(c x)\right ) \text {Li}_2\left (1-\frac {2 c (d+e x)}{(c d+i e) (1-i c x)}\right )}{c^2 d^2+e^2}-\frac {3 b^3 c \text {Li}_3\left (1-\frac {2}{1-i c x}\right )}{2 \left (c^2 d^2+e^2\right )}+\frac {3 b^3 c \text {Li}_3\left (1-\frac {2 c (d+e x)}{(c d+i e) (1-i c x)}\right )}{2 \left (c^2 d^2+e^2\right )}-\frac {\left (6 b^2 c^2\right ) \int \frac {\left (a+b \tan ^{-1}(c x)\right ) \log \left (\frac {2}{1+i c x}\right )}{1+c^2 x^2} \, dx}{c^2 d^2+e^2}\\ &=\frac {i c \left (a+b \tan ^{-1}(c x)\right )^3}{c^2 d^2+e^2}+\frac {c^2 d \left (a+b \tan ^{-1}(c x)\right )^3}{e \left (c^2 d^2+e^2\right )}-\frac {\left (a+b \tan ^{-1}(c x)\right )^3}{e (d+e x)}-\frac {3 b c \left (a+b \tan ^{-1}(c x)\right )^2 \log \left (\frac {2}{1-i c x}\right )}{c^2 d^2+e^2}+\frac {3 b c \left (a+b \tan ^{-1}(c x)\right )^2 \log \left (\frac {2}{1+i c x}\right )}{c^2 d^2+e^2}+\frac {3 b c \left (a+b \tan ^{-1}(c x)\right )^2 \log \left (\frac {2 c (d+e x)}{(c d+i e) (1-i c x)}\right )}{c^2 d^2+e^2}+\frac {3 i b^2 c \left (a+b \tan ^{-1}(c x)\right ) \text {Li}_2\left (1-\frac {2}{1-i c x}\right )}{c^2 d^2+e^2}+\frac {3 i b^2 c \left (a+b \tan ^{-1}(c x)\right ) \text {Li}_2\left (1-\frac {2}{1+i c x}\right )}{c^2 d^2+e^2}-\frac {3 i b^2 c \left (a+b \tan ^{-1}(c x)\right ) \text {Li}_2\left (1-\frac {2 c (d+e x)}{(c d+i e) (1-i c x)}\right )}{c^2 d^2+e^2}-\frac {3 b^3 c \text {Li}_3\left (1-\frac {2}{1-i c x}\right )}{2 \left (c^2 d^2+e^2\right )}+\frac {3 b^3 c \text {Li}_3\left (1-\frac {2 c (d+e x)}{(c d+i e) (1-i c x)}\right )}{2 \left (c^2 d^2+e^2\right )}-\frac {\left (3 i b^3 c^2\right ) \int \frac {\text {Li}_2\left (1-\frac {2}{1+i c x}\right )}{1+c^2 x^2} \, dx}{c^2 d^2+e^2}\\ &=\frac {i c \left (a+b \tan ^{-1}(c x)\right )^3}{c^2 d^2+e^2}+\frac {c^2 d \left (a+b \tan ^{-1}(c x)\right )^3}{e \left (c^2 d^2+e^2\right )}-\frac {\left (a+b \tan ^{-1}(c x)\right )^3}{e (d+e x)}-\frac {3 b c \left (a+b \tan ^{-1}(c x)\right )^2 \log \left (\frac {2}{1-i c x}\right )}{c^2 d^2+e^2}+\frac {3 b c \left (a+b \tan ^{-1}(c x)\right )^2 \log \left (\frac {2}{1+i c x}\right )}{c^2 d^2+e^2}+\frac {3 b c \left (a+b \tan ^{-1}(c x)\right )^2 \log \left (\frac {2 c (d+e x)}{(c d+i e) (1-i c x)}\right )}{c^2 d^2+e^2}+\frac {3 i b^2 c \left (a+b \tan ^{-1}(c x)\right ) \text {Li}_2\left (1-\frac {2}{1-i c x}\right )}{c^2 d^2+e^2}+\frac {3 i b^2 c \left (a+b \tan ^{-1}(c x)\right ) \text {Li}_2\left (1-\frac {2}{1+i c x}\right )}{c^2 d^2+e^2}-\frac {3 i b^2 c \left (a+b \tan ^{-1}(c x)\right ) \text {Li}_2\left (1-\frac {2 c (d+e x)}{(c d+i e) (1-i c x)}\right )}{c^2 d^2+e^2}-\frac {3 b^3 c \text {Li}_3\left (1-\frac {2}{1-i c x}\right )}{2 \left (c^2 d^2+e^2\right )}+\frac {3 b^3 c \text {Li}_3\left (1-\frac {2}{1+i c x}\right )}{2 \left (c^2 d^2+e^2\right )}+\frac {3 b^3 c \text {Li}_3\left (1-\frac {2 c (d+e x)}{(c d+i e) (1-i c x)}\right )}{2 \left (c^2 d^2+e^2\right )}\\ \end {align*}
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Mathematica [A] time = 21.65, size = 770, normalized size = 1.54 \[ -\frac {a^3}{e (d+e x)}+\frac {3 a^2 b c^2 d \tan ^{-1}(c x)}{c^2 d^2 e+e^3}-\frac {3 a^2 b c \log \left (c^2 x^2+1\right )}{2 \left (c^2 d^2+e^2\right )}+\frac {3 a^2 b c \log (d+e x)}{c^2 d^2+e^2}-\frac {3 a^2 b \tan ^{-1}(c x)}{e (d+e x)}+\frac {3 a b^2 \left (-\frac {c d \left (-\frac {1}{2} \pi \log \left (c^2 x^2+1\right )+i \text {Li}_2\left (e^{2 i \left (\tan ^{-1}\left (\frac {c d}{e}\right )+\tan ^{-1}(c x)\right )}\right )-i \tan ^{-1}(c x) \left (\pi -2 \tan ^{-1}\left (\frac {c d}{e}\right )\right )-2 \left (\tan ^{-1}\left (\frac {c d}{e}\right )+\tan ^{-1}(c x)\right ) \log \left (1-e^{2 i \left (\tan ^{-1}\left (\frac {c d}{e}\right )+\tan ^{-1}(c x)\right )}\right )+2 \tan ^{-1}\left (\frac {c d}{e}\right ) \log \left (\sin \left (\tan ^{-1}\left (\frac {c d}{e}\right )+\tan ^{-1}(c x)\right )\right )-\pi \log \left (1+e^{-2 i \tan ^{-1}(c x)}\right )\right )}{c^2 d^2+e^2}-\frac {\tan ^{-1}(c x)^2 e^{i \tan ^{-1}\left (\frac {c d}{e}\right )}}{e \sqrt {\frac {c^2 d^2}{e^2}+1}}+\frac {x \tan ^{-1}(c x)^2}{d+e x}\right )}{d}+\frac {b^3 \left (\frac {2 x \tan ^{-1}(c x)^3}{d+e x}+\frac {2 \tan ^{-1}(c x) \left (\tan ^{-1}(c x)^2 \left (-2 e \sqrt {\frac {c^2 d^2}{e^2}+1} e^{i \tan ^{-1}\left (\frac {c d}{e}\right )}+i c d+e\right )+3 c d \left (2 \tan ^{-1}\left (\frac {c d}{e}\right ) \left (\log \left (\frac {e^{-i \tan ^{-1}\left (\frac {c d}{e}\right )} \left ((c x-i) e^{2 i \tan ^{-1}\left (\frac {c d}{e}\right )}+c x+i\right )}{2 \sqrt {c^2 x^2+1}}\right )+\log \left (1-e^{2 i \left (\tan ^{-1}\left (\frac {c d}{e}\right )+\tan ^{-1}(c x)\right )}\right )-\log \left (\sin \left (\tan ^{-1}\left (\frac {c d}{e}\right )+\tan ^{-1}(c x)\right )\right )-\log \left (-i e^{2 i \tan ^{-1}\left (\frac {c d}{e}\right )} \sin \left (2 \tan ^{-1}(c x)\right )-e^{2 i \tan ^{-1}\left (\frac {c d}{e}\right )} \cos \left (2 \tan ^{-1}(c x)\right )+1\right )\right )+\pi \left (\log \left (1+e^{-2 i \tan ^{-1}(c x)}\right )-\log \left (-\frac {2 i}{c x-i}\right )\right )\right )+3 c d \tan ^{-1}(c x) \left (2 \log \left (1-e^{2 i \left (\tan ^{-1}\left (\frac {c d}{e}\right )+\tan ^{-1}(c x)\right )}\right )-\log \left (-i e^{2 i \tan ^{-1}\left (\frac {c d}{e}\right )} \sin \left (2 \tan ^{-1}(c x)\right )-e^{2 i \tan ^{-1}\left (\frac {c d}{e}\right )} \cos \left (2 \tan ^{-1}(c x)\right )+1\right )\right )\right )-6 i c d \tan ^{-1}(c x) \text {Li}_2\left (e^{2 i \left (\tan ^{-1}\left (\frac {c d}{e}\right )+\tan ^{-1}(c x)\right )}\right )+3 c d \text {Li}_3\left (e^{2 i \left (\tan ^{-1}\left (\frac {c d}{e}\right )+\tan ^{-1}(c x)\right )}\right )}{c^2 d^2+e^2}\right )}{2 d} \]
Warning: Unable to verify antiderivative.
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fricas [F] time = 0.43, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {b^{3} \arctan \left (c x\right )^{3} + 3 \, a b^{2} \arctan \left (c x\right )^{2} + 3 \, a^{2} b \arctan \left (c x\right ) + a^{3}}{e^{2} x^{2} + 2 \, d e x + d^{2}}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [C] time = 1.23, size = 2960, normalized size = 5.93 \[ \text {output too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \frac {3}{2} \, {\left ({\left (\frac {2 \, c d \arctan \left (c x\right )}{c^{2} d^{2} e + e^{3}} - \frac {\log \left (c^{2} x^{2} + 1\right )}{c^{2} d^{2} + e^{2}} + \frac {2 \, \log \left (e x + d\right )}{c^{2} d^{2} + e^{2}}\right )} c - \frac {2 \, \arctan \left (c x\right )}{e^{2} x + d e}\right )} a^{2} b - \frac {a^{3}}{e^{2} x + d e} - \frac {\frac {15}{2} \, b^{3} \arctan \left (c x\right )^{3} - \frac {21}{8} \, b^{3} \arctan \left (c x\right ) \log \left (c^{2} x^{2} + 1\right )^{2} - {\left (e^{2} x + d e\right )} \int \frac {196 \, {\left (b^{3} c^{2} e x^{2} + b^{3} e\right )} \arctan \left (c x\right )^{3} + 12 \, {\left (64 \, a b^{2} c^{2} e x^{2} + 15 \, b^{3} c e x + 15 \, b^{3} c d + 64 \, a b^{2} e\right )} \arctan \left (c x\right )^{2} - 84 \, {\left (b^{3} c^{2} e x^{2} + b^{3} c^{2} d x\right )} \arctan \left (c x\right ) \log \left (c^{2} x^{2} + 1\right ) - 21 \, {\left (b^{3} c e x + b^{3} c d - {\left (b^{3} c^{2} e x^{2} + b^{3} e\right )} \arctan \left (c x\right )\right )} \log \left (c^{2} x^{2} + 1\right )^{2}}{8 \, {\left (c^{2} e^{3} x^{4} + 2 \, c^{2} d e^{2} x^{3} + 2 \, d e^{2} x + d^{2} e + {\left (c^{2} d^{2} e + e^{3}\right )} x^{2}\right )}}\,{d x}}{32 \, {\left (e^{2} x + d e\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {{\left (a+b\,\mathrm {atan}\left (c\,x\right )\right )}^3}{{\left (d+e\,x\right )}^2} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\left (a + b \operatorname {atan}{\left (c x \right )}\right )^{3}}{\left (d + e x\right )^{2}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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